[Hemanth_2u]

8. Four married couples 'played a tennis tournament of 'mixed doubles'. A man and a woman always played against a man and a woman. However, no person zver played with or against any other person more than once. They all played together in two courts on three successive days.


Can you show how they could have done it?
Ans:
Call the men A, B, D, E and their wives a, b, d, e. Then they may play
as follows without any person ever playing twice with or against any
other person:--
First Court. Second Court.
1st Day | A d against B e | D a against E b
2nd Day | A e against D b | E a against B d
3rd Day | A b against E d | B a against D e
It will be seen that no man ever plays with or against his own wife--an
ideal arrangement. If the reader wants a hard puzzle, let him try to
arrange eight married couples (in four courts on seven days) under
exactly similar conditions.


Edited by: Hemanth_2u