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schava_pavan · 27-01-08, 11:41 PM

HAI smileey ur approach. is good....but ur answer is correct ,only half the way... but rest goes on like this... the base of the pythagorus traingle.. takes the diameter of the cylinder then it becomes...dia*pi.=32....so the diameter becomes 10.19
hence now. length of creep for one twist becomes sqrt((10.19^2)+(60^2))=60.84
so length of complete creep is (4*60.84)=243.36..
so the answer is 243.36..... but clue for this i got from ur solution... only

27-01-08, 11:41 PM	#4 (permalink)
schava_pavan Junior Member Join Date: Jan 2008 Location: hyderabad Posts: 13 Thanks: 0 Thanked 0 Times in 0 Posts Thanks: 0 Thanked 0 Times in 0 Posts Rep Power: 1	Re: Puzzle Contest-141 HAI smileey ur approach. is good....but ur answer is correct ,only half the way... but rest goes on like this... the base of the pythagorus traingle.. takes the diameter of the cylinder then it becomes...diapi.=32....so the diameter becomes 10.19* hence now. length of creep for one twist becomes sqrt((10.19^2)+(60^2))=60.84 so length of complete creep is *(460.84)=243.36.. so the answer is 243.36..... but clue for this i got from ur solution... only**