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Old 25-01-07, 11:03 AM   #1 (permalink)
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The sum of the digits of a two digit number is 8. When

The sum of the digits of a two digit number is 8. When 18 is added to the number, the digits are reversed. Find the number?
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Old 26-01-07, 01:22 PM   #2 (permalink)
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Re: The sum of the digits of a two digit number is 8. When

Let the two digits of the number be : x and y, then the number is 10x * y
Given :
x + y = 8 -- (1)
((10 * x) + y ) + 18 = ( 10 *y) + x
=> 9*x - 9 *y = -18 -- (2)
Solving (1) and (2) we get
x = 3 and y= 5 so the number is : 35 such that 35 + 18 = 53,reverse of the original number
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Old 18-03-08, 02:35 PM   #3 (permalink)
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Re: The sum of the digits of a two digit number is 8. When

The sum of the digits of a two digit number is 8. When 18 is added to the number, the digits are reversed. Find the number?

It will be 35 when we add 18 in it. It becomes 53
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Old 13-07-08, 12:53 PM   #4 (permalink)
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Re: The sum of the digits of a two digit number is 8. When

Quote:
Originally Posted by PrashanthU View Post
Let the two digits of the number be : x and y, then the number is 10x * y
Given :
x + y = 8 -- (1)
((10 * x) + y ) + 18 = ( 10 *y) + x
=> 9*x - 9 *y = -18 -- (2)
Solving (1) and (2) we get
x = 3 and y= 5 so the number is : 35 such that 35 + 18 = 53,reverse of the original number
hi

how did you get 10x * y?

confusing......

pls reply
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Old 24-07-08, 04:35 PM   #5 (permalink)
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Re: The sum of the digits of a two digit number is 8. When

its simple,any 2 digit no is represented as 10x+y
eg-11=10*1+1
it is standard form of representing a 2 digit no
in the same way 3 digit no-100x+10y+z
...
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