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Sum of the numbers from 1 to 100 if the digit 6
Sum of the numbers from 1 to 100 if the digit 6 is replaced by 9 in those number?
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Re: Sum of the numbers from 1 to 100 if the digit 6
Sum of the first 'n' natural number is given by : (n * (n +1))/2
=> (100 * 101) / 2 = 5050 Also, 6 appears 20times(6,16,,26,36,46,56,60,61,62,63,64,65,66,67,68,69,76,86,96) in a span of first 100 natural numbers and since 6 is replaced by 9 the difference of ( 9 - 6 ) = 3 for 20 times comes to : 60 So, the final answer is : 5050 + 60 = 5110
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