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| Senior Member Join Date: Jan 2007 Age: 24
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Rep Power: 13 | a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2 a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2 days,remaining work completed by c. In how many days work is completed? |
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| Junior Member Join Date: Nov 2008 Age: 24
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Rep Power: 2 | Re: a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2 A's 2 days work=2/6=1/3; B & c 2 day work=2(1/8+1/10)=9/20; Total work done by A,B,C in 4 days=1/3+9/20=4/5; Remaining work=1-4/5=1/5; C does 1/10 of work in 1 day C does 1/5 of work in x days x=2; Total days taken by c to finish remaining work=2; Total number of days taken by A,B,C to finish work=2+2+2=6 Days ![]() |
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| Junior Member Join Date: Oct 2009
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Rep Power: 1 | Re: a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2 @aysnapraveen ... how did u get 4/5...?? (1/3)+(9/20)=47/60, remaining work is 1-47/60= 13/60 remaining work can be done by c is (13/60)*10= 2.166days so tatal days are 2+2+2.166 = 6.166days |
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