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a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2

        

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Old 29-01-07, 01:00 PM   #1 (permalink)
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a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2

a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2 days,remaining work completed by c. In how many days work is completed?

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Old 18-11-08, 10:08 PM   #2 (permalink)
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Re: a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2

A's 2 days work=2/6=1/3;
B & c 2 day work=2(1/8+1/10)=9/20;
Total work done by A,B,C in 4 days=1/3+9/20=4/5;
Remaining work=1-4/5=1/5;
C does 1/10 of work in 1 day
C does 1/5 of work in x days
x=2;
Total days taken by c to finish remaining work=2;
Total number of days taken by A,B,C to finish work=2+2+2=6 Days
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Old 14-10-09, 01:29 PM   #3 (permalink)
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Re: a ,b,c can do a work in 6,8,10 days a works for 2 days. b&c for 2

@aysnapraveen ... how did u get 4/5...??
(1/3)+(9/20)=47/60,
remaining work is 1-47/60= 13/60
remaining work can be done by c is (13/60)*10= 2.166days
so tatal days are 2+2+2.166 = 6.166days
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