Aptitude Contest - 58

[HELP]

1. If the digit in the unit's place
of a two-digit number is halved and the digit in the ten’s f place is doubled,
the number thus obtained is equal to the number obtained by interchanging the
digits. Which of the following is definitely[/b]




(a) Sum of
the digits is a two-digit number.


(b) Digit in the unit's place is twice the digit in the
ten's place.


(c) Digits in the unit's place and the ten's place are
equal.


(d)
Digit in the unit's place is half of the digit in the ten's place.






(e)
None of these






2. If the number obtained on
interchanging the digits of a two-digit number is 18 more than the original
number and the sum of the digits is 8, then what is the original number?[/b]


(a) 26


(b) 35


(c) 53


(d) Cannot
be determined




(e) None of these






3. The difference between a two-digit
number and the number obtained by interchanging the digits is 36. What is the
difference between the sum and the difference of the digits of the number if
the ratio between the digits of the number is 1 : 2 ?[/b]


(a) 4


(b) 8


(c) 16










(e) None
of these








4. A number consists of 3 digits
whose sum is 10. The middle digit is equal to the Sum of the other two and the
number will be increased by 99 if its digits are reversed. The number is : [/b]




(a) 145


(b) 253


(c) 370






(d) 352






5. A [/b]two-digit
number becomes five-sixth of itself when its digits are reversed. The two
digits differ by one. The number [/b]is :[/b]


(a) 45


(b) 54


(c) 56


(d) 65

[indian]

(1)b (2) b (3)b (4)d (5)b

[akkina_swetha]

(1)b(2)b(3)b(4)b(5)b

[keshaviinturi]

1) d
2) b
3) a
4) b Explanation:-
a+b+c=10 (given)
cba-abc=99 (given)
b=a+c
100c+10b+a-100a-10b-c=99
99c-99a=99
c-a=1
c=1+a so, substitute these values in a+b+c=10.
then, a+(a+c)+(1+a)=10
a+a+1+a+1+a=10, so, a=2, b=5, c=3
the number is 253.

5) a