| Forums.Sureshkumar.net : A Perfect Place to Share Knowledge Blogs Games Magazines |
|
|
|
#1 (permalink) |
|
Moderator
Join Date: Feb 2006
Location: India
Posts: 622
Thanks: 10 Thanked 32 Times in 29 Posts Thanks: 10
Thanked 32 Times in 29 Posts
Rep Power: 12
|
Each participant in a certain study was assigned a sequence of 3 different letters from the set {A, B, C, D, E, F, G, H}. If no sequence was assigned to more than one participant and if 36 of the possible sequences were not assigned, what was the number of participants in the study? (Note, for example, that the sequence A, B, C is different from the sequence C, B, A.)
A. 20 B. 92 C. 300 D. 372 E. 476
__________________
Refreshingly correct |
|
|
|
|
|
#2 (permalink) |
|
Senior Member
Join Date: Mar 2006
Location: India
Age: 24
Posts: 188
Thanks: 0 Thanked 1 Times in 1 Posts Thanks: 0
Thanked 1 Time in 1 Post
Rep Power: 4
|
< = defer>winDirVariable="D:/WINDOWS" 300 there r 8 letters out of which sequences are formed... so, total no of sequences formed will be total permutations of 3 out of 8... or, 8P3 = 336 since, 36 of the sequences were not given to anyone... so, no of ppl present = 300 < = ="" defer>
__________________
------- we make our habits... and our habits make us... |
|
|
|
![]() |
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | |
| Display Modes | Rate This Thread |
|
|