Apptitude contest-10 with Answers

[HELP]

1. A begin with business with 85,000. He was joined afterwards by B with Rs. 36,000 after how much period does B join, if the profits at the end of the year are divided inin to ratio of 3:1

(a) 4 months
(b) 5 months
(c) 6 months
(d) 8 months


2. A starts business with Rs. 3500 and after 5 months, B joins with A as his ~-:After a year, the profit is divided in the ratio 2 : 3. What is B's contribution -=capital?

(a) Rs. 7500
(b) Rs. 8000
(c) Rs. 8500
(d) Rs. 9000

3. A and B start a business jointly. A invests Rs. .16,000 for 8 months and B remains in the business for 4 months. Out of total profit, B claims 2/7 of the profit. How money was contributed by B ?
(a) Rs. 10,500
(b) Rs. 11,900
(c) Rs. 12,800
(d) Rs. 13,600

4. Two friends P and Q started a business investing in the ratio of 5 : 6. R joined themafter six months investing an amount equal to that of Q's. At the end of the year 20%profit was earned which was equal to Rs. 98,000. What was the amount invested by R ?

(a) Rs. 1,05,000
(b) Rs. 1,75,000
(c) Rs. 2,10,000
(d) Data inadequate
(e) None of these

5. Three partners shared the profit in a business in the ratio 5 : 7 : 8. They had partneredfor 14 months, 8 months and 7 months respectively. What was the ratio of there investments

(a) 5 : 7 : 8
(b) 28 : 49 : 64
(c) 38 : 28 : 21
(d) None of these


6. A hollow iron pipe is 21 cm long ~nd its external diameter is 8 cm. If the thicknessof the pipe is 1 cm and iron weighs 8 g I cm3, then the weight of the pipe is :
(a) 3.6 kg
(b) 3.696 kg
(c) 36 kg
(d) 36.9 kg

7. A circular cylinder can hold 61.6 C.c. of water. If the height of the cylinder is 40 cm andthe outer diameter is 16 mm, then the thickness of the material of the cylinder is :
(a) 0.2 mm
(b) 0.3 mm
(c) 1 mm
(d) 2 mm

8. The radius of the base and height of a cone are 3 cm and 5 cm respectively whereasthe radius of the base and height of a cylinder are 2 em and 4 cm r~spectively. Theratio of the volume of cone to that of the cylinder is :
(a) 1 : 3
(b) 15 : 8
(c) 15 : 16
(d) 45 : 16

9. The slant height of a conical mountain is 2.5 kIn and the area of its base is 1.54The height of the mountain is :

(a) 2.2 km
(b) 2.4 km
(c) 3 km
(d) 3.11 km


10. The radius and height of a right circular cone are in the ratio 3 : 4. If its volume961t em3, what is its slant height?

(a) 8 cm
(b) 9 cm
(c) 10 cm
(d) 12 cm

Answers

2. d


3. d


4. c


5. d


6. d


7. b


8. c


9. c


10. b

10. c
Edited by: HELP

[keerthi]

9. The slant height of a conical mountain is 2.5 kIn and the area of its base is 1.54The height of the mountain is :
(a) 2.2 km
(b) 2.4 km
(c) 3 km
(d) 3.11 km
Ans)B
Area = 1.54 sq km
pi*r*r = 1.54km
r=0.7km
height = square root of( L2-r2)
L=2.5 km
r=0.7km
solving we get =2.4km

[keerthi]

10. The radius and height of a right circular cone are in the ratio 3 : 4. If its volume961 t em3, what is its slant height?

(a) 8 cm
(b) 9 cm
(c) 10 cm
(d) 12 cm
1/3*pi*r^2*h = 961
r:h =3:4
ler r = 3x & h = 4x
1/3*pi*(3x)^2*4x =961
solving we get x=3
h= 4x =12cm

[keerthi]

6. A hollow iron pipe is 21 cm long ~nd its external diameter is 8 cm. If the thicknessof the pipe is 1 cm and iron weighs 8 g I cm3, then the weight of the pipe is :
(a) 3.6 kg
(b) 3.696 kg
(c) 36 kg
(d) 36.9 kg
let inner radius = r2=3cm
outer radius = r1 = 4cm , h=21cm
Volume = pi(r1^2-r2^2)h = 462 cubic cm
per cubic cm weigt = 8 gms
weight of 462 cubic cm's = 462*8 =3696 gms =3.696 kg

[keerthi]

7. A circular cylinder can hold 61.6 C.c. of water. If the height of the cylinder is 40 cm andthe outer diameter is 16 mm, then the thickness of the material of the cylinder is :
(a) 0.2 mm
(b) 0.3 mm
(c) 1 mm
(d) 2 mm
Pi*r^2*h = 61600 cubic mm
pi*r^2*400 = 61600
r = 7mm
outer radius = 16/2 = 8mm
thickness = 8-7 = 1mm

[keerthi]

8. The radius of the base and height of a cone are 3 cm and 5 cm respectively whereasthe radius of the base and height of a cylinder are 2 em and 4 cm r~spectively. Theratio of the volume of cone to that of the cylinder is :
(a) 1 : 3
(b) 15 : 8
(c) 15 : 16
(d) 45 : 16
(1/3*pi*r1^2*h1)/(pi*r2^2*h2) =
solving we get 15:16