Aptitude contest - 107

[HELP]

1. The area of a field in the shape of a trapezium measures 1440 m2.
The perpendicular distance between its parallel sides is 24 m. If the
ratio of the parallel sides is 5 : 3,the length of the longer parallel
side is :



(a) 45 m

(b) 60 m

(c) 75 m

(d) 120 m



2. The cross-section of a cana! is trapezium in shape. The canal is 12
m wide at the top and 8 m wide at the bottom. If the area of the
cross-section is 840 sq. m. the depth of the canal is :

(a) 8.75 m

(b) 42 m

(c) 63 m

(d) 84 m



3. The area of a circle of radius 5 is numerically what percent of its circumference?

(a) 2.00

(b) 225

(c) 240

(d) 250



4. A man runs round a circular field of radius 50 m at the speed of 12
kIn I hr. What is the time taken by the man to take twenty rounds of
the field?



(a) 30 min.

(b) 32 min.

(c) 34 min.

(d) None of these



5. A cow is tethered in the middle of a field with a 14 feet long rope.
If the cow grazes 100 sq. ft. per day, then approximately what time
will be taken by the cow to graze the whoe field ?



(a) 2 days

(b) 6 days

(c) 18 days

(d) 24 days

(e) None of these

[gunjan.sethia]

5. b (only she can graze 616 sq ft)Edited by: gunjan.sethia

[WISDOM]

1,2 : tell me the area of trapezium!


3.(d) x = (pi)r*r / (2 pi r) = r/2 * 100 % = 50 r %= 250%


4.(b) speed is 12 km/ hr, right?
20 rounds = 2 pi r * 20 = 2000*pim

time taken = 2000*pi / (12000) hr = pi/6 hr = 10 pi minutes = 31.4 minutes~ 32 minutes


5. (b)total area that cow will graze = 196 pi sq feet = 616 sq feet
days = 616/100 = 6.16 days i.e. 6 days and arnd 4 hrs

[Anusha_j]

1. area of trapezium= 1/2 * h * (a+b)
a:b = 5:3
b = 3a/5
1/2 * 24 * (a+3a/5) = 1440
a = 75m

2. 1/2 * h * (8+12) = 840
h = 84m

3. 250