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Hi friends solve this problem.and explain the approach. A certain number of men can finish a piece of work in 10 days. If however there were 10 men less it will take 10 days more for the work to be finished. How many men were there originally? ANS:110 plz let me know the hw to solve these type probs. regrds varun |
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#2 (permalink) |
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hi,
check ur given data.u have typed 10 instead of 100 wrongly. Originally,let there be x men. Less men , more days(indirect proposition) (x-10):x::100:110 (x-10)*110=x*100 ANS: x=110 ABI.
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#3 (permalink) |
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Hi Abeetha,
I am confused. Can you please explain me how you got those equations? Thanks, Krishna
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#4 (permalink) |
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A certain number of men can finish a piece of
work in 100 days. If however there were 10 men less it will take 10 days more for the work to be finished. How many men were there originally? Solution: Originally,let there be x men According to 2nd line,10 men less. So,less men means it takes more days to finish.Hence it is an indirect proposition. Days 100 110::Men x (x-10) (x-10)*110=x*100 Ans:110
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Let 1 man's 1 day work = w so n man's 10 day work = 10 n w (n-10) (20) w = 10 man less than n will take 10 days more (i.e. 20 days) and one man's 1 day work remains same since work is same, sp 10nw = 20(n-10)w => n =20 arre!!!! my ans is wrong ![]() abeetha was right! it shud' be 100 days. ty abeetha ![]() 100 n w = 110(n-10)w => n = 110 ![]()
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