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Old 09-07-06, 08:23 PM   #1 (permalink)
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Dear friends,
please solve this

1)A cow is standing 5 feet from the middle of the bridge. A train is coming towards the cow at speed of 90 miles per hour from the near end and the train is twice as long as the bridge. If the cow had tried to move forward in the same direction as of the train then the cow would have got hit be three feet. But it moved in opposite direction to the train and saved by one feet. Then What is the length of the bridge?


2)Two ships start from the opposite banks of river
perpendicular to banks.
Both are going at constant speed. One is faster than
the other. They meet
at 720 m from nearest bank. Then they go ahead upto
the other end of banks
and wait there for 10 minutes. Then they again come
back and meet 400m far
from the other bank. find out what is the width of
river.
3)Two men are goingalong a trackf rail in the opposite
direction.One goods train crossed the first person in 20 sec.
After 10 min the train crossed the other person who is commingin
opposite directionin 18 sec .After the train haspassed, when the two will meet?
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Old 10-07-06, 04:24 AM   #2 (permalink)
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1. dobara mat poochna!!!!!!!!!!!!!!!! chek it out http://www.sureshkumar.net/forum/for...ID=19765#19765

2. (w-720)/720 = s2/s1 = (W+320)/(W-320)

=> w = 1760


PS: this question seems to be the fav one by infosys. here's the direct mantra for this. i hope i have not messed up anywhere. use the following formula and u will get the correct answer although there's no need for using it; u can solve it directly anyways

direct mantra:: 2*first dist. given + (second dist. - first dist.)given

= 2*720 +(720-400) = 1760 [img]smileys/smiley2.gif[/img]


3. This is a very difficult question and i had tried to solve it some time back. kindly visit this link if u need the answer



When r u supposed to appear for the infosys test? do tell me!

Good Luck [img]smileys/smiley20.gif[/img]



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