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urgent.plz solve
hi,
A family has 20 members & 20 breads.Half bread to every child,2 to every lady,3 to every man.How many children,ladies,men in the family?
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Re: urgent.plz solve
c/2 + 2W + 3M = 20
c + w + m = 20 c can only be even no. w<10 coz' when w<=10 then 2w exceeds 20, the total no. of breads from this u can say that w<=8 coz' c shud' be at least 2 and m shud' be at least 1 again same reasoning M<=5 ......................blah blah................... now let's solve the problem: u have 2 equations: c + m + w = 20 and c/2 + 3m + 2w = 20 multiply 2nd equation with 2 and subtract the 2 equations, u get 3w + 5m = 20 only m=1 will give integral value for w => m = 1 , w=5, c = 14 Interpretation: 1 man, 5 women and 14 children, pretty interesting, huh? :)
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