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Old 14-05-06, 02:09 PM   #1 (permalink)
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1. A frog goes 3 metres up in a well in a day and goes 2 metre

down in night. How time will it take to cover 30 metres.



2. A+B+C+D=D+E+F+G=G+H+I=17 .A to I are different digits between 1

to 9. A=4.Find the value of D & G.



3. Find the number of numbers that can be formed by assuming one

number left to 15 and one right to 15 so that the 4 digit number

so formed is exactly divisble by 15.



4. There is a faulty weighing machine such that if there is a one

kg weight on one side, then 8 melons are equivalent on the other

side of weighing machine....If the 1kg weight is placed on the

other side, then 2 melons weigh equal to the 1 kg stone.....what

is the weight of the melon? please note that all melons weigh

equal



5. work can be done by 4 people in 32 days . how many more days

will it take if 16 people join them 2 days after?



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Old 15-05-06, 03:28 AM   #2 (permalink)
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1. A frog goes 3 metres up in a well in a day and goes 2 metre


down in night. How time will it take to cover 30 metres.



Ans: 27days + 27 nights + 1 day



totally==28days +27 nights


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Old 15-05-06, 03:43 AM   #3 (permalink)
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5. work can be done by 4 people in 32 days . how many more days


will it take if 16 people join them 2 days after?



Ans: remaining days is 6 days...

Total time is 2+ 6 =8 days...



Sol: take work done by 1 people on one day is 1 work..

Then work done by 4 people on one day is 4..

So, total work is 4X 32 =128 work



First 2 days, work done by 4 people.. completed work is 8...

Remaining work is 128-8=120..



Total people for remaining days is 4+16=20



total day remaining is 120/20 = 6 days


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Old 01-06-06, 09:19 AM   #4 (permalink)
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HI,


3.four
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Old 06-07-06, 06:27 AM   #5 (permalink)
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4. let offset on left side be t1 and offset on right side is t2. that is if u add t1 on left side and t2 on right side, then both wts will show correct reading or u can say add t1 on left side and t2 on right side with nothing else in them, then the 2 wts are equal. ok?


now let wt of each melon is xxx


then 1 kg + t1 = 8xxx + t2

=> t2-t1 = 8xxx - 1


again, 2xxx+t1 = 1 kg + t2

=> t2 - t1 = 2xxx - 1


=> 6xxx = 2

or xxx = 1/3 kg = wt of each melon


4. 6 days is right by Ms Rena


2. i always forget this!!!!!!!


3. many nos. 33 nos. divisible by 15 in which ab15 where a,b may be same

u can calculate for 15ab also
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Old 18-07-06, 02:54 PM   #6 (permalink)
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Re: Puzzles contest - 87

2) A+B+C+D=D+E+F+G=G+H+I=17
A=4 Find the values of D&G?
A) A+B+C+D+E+F+G+H+I+(D+G)=17*3
Sum Of First n Natural Numbers =n(n+1)/2
=9*10/2
=45
45+(D+G)=51
(D+G)=6
The Possible values for D& G are {1,5} {5,1}
Suppose D=1 and G=5
A+B+C+D=17
4+B+C+1=17
B+C=12
The Possible Values can be {3,9}{9,3}
If We Take B=3 n C=9 then
4
3
9
1 E F 5
E+F has to be 11
The POssible Values can be {(2,9),(9,2),(3,8)(8,3),(6,5),(5,6)}
But We can't Take any of the values
So our assumption d=1, n g=5 is wrong
So D=5 N G=1
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Old 18-07-06, 03:31 PM   #7 (permalink)
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Re: Puzzles contest - 87

3)To Be Divisble By 15 it must be divisible by 5 n 3
So the last digit must be 5 or 0
The Numbers Are
1 1 5 5 3 1 5 0
4 1 5 5 6 1 5 0
7 1 5 5 9 1 5 0
So Total 6
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Old 19-07-06, 02:27 PM   #8 (permalink)
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Thumbs up Re: Puzzles contest - 87

Quote:
Originally Posted by Shanthi_2384
3)To Be Divisble By 15 it must be divisible by 5 n 3
So the last digit must be 5 or 0
The Numbers Are
1 1 5 5 3 1 5 0
4 1 5 5 6 1 5 0
7 1 5 5 9 1 5 0
So Total 6
u r absolutely right! i was stupid to not even read the question properly.
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