puzzles

[sapna]

plz.. i want ans for these puzzles with explanations

1)one day i was going somewhere.I found CHARITY 1,CHARITY 2,CHARITY3
.for charity 1 I gave half of the money i have plus one rupee,charity 2
I gave half of the money that was remaining with me i plus 2
rupee,charity 3 I gave half of the money that was remainingi plus 3
rupee,finally i was left with rs1 only. what amt i had
initally?

[iCanSolveIt]

hi

ANS 42

let the no be x

to 1st charity = x/2 + 1

remaining money = x/2 - 1

to 2nd charity = x/4 - 1/2 +2 = x/4+ 3/2

remaining = x/2 - 1 - (x/4+ 3/2) = x/4- 5/2

to 3rd charity = x/8 - 5/4 + 3 = x/8+ 7/4

remaining = x/4 - 5/2 - (x/8+ 7/4) = 1

(x-10)/4 - (x + 14)/8 = 1

2x - 20 - x - 14 =8

x =42

[sapna]

thank u

[SHUBH]

Simplest method:

Start from end

at end she was having 1 rupee

so money left after 3rd charity= 3+1=4 which is half of 8

money left after2nd charity =8+2=10 which is half of 20

money left after 1st charity =20+1=21 which is half of 42.

So, initially she was having 42 rupees.

[Rena]

Hi sairam,


Good method ya.Oh god.i was also thinking like having x.But this is easiest and simple method.Good.