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Old 18-05-06, 03:23 PM   #1 (permalink)
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SOLUTION PLZ

q)
.in
a garden there are 10 rows and 12 columns of mango trees. the distance btween
each tree is 2 metres and a distance of one meter is left from all sides of the
boundary of the garden. the length of the garden is


OPTIONS:_a)20 m b)22m c)24m d)26m


2)


a
watch ,which gains uniformly is 2min.show at noon on monday,and is 4min.48
seconds fast at 2pm.on the follwing monday.when was it correct?


a)2
days 6hrs b)2 days 2 hrs c)3days 1hr d)3days 6hrs



3)on
the occasion of a certain meeting each member gave shake hand to the remaining
number.if the total shake were 1176,how many members were present for the
meeting.


a)48
b)58 c)49 d)59






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Old 19-05-06, 01:24 AM   #2 (permalink)
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in a garden there are 10 rows and 12 columns of mango trees. the distance btween each tree is 2 metres and a distance of one meter is left from all sides of the boundary of the garden. the length of the garden is

OPTIONS:_a)20 m b)22m c)24m d)26m
ANS. c)24

on the occasion of a certain meeting each member gave shake hand to the remaining number.if the total shake were 1176,how many members were present for the meeting.
a)48 b)58 c)49 d)59
ANS. c)49
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Old 19-05-06, 09:39 AM   #3 (permalink)
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2)
a watch ,which gains uniformly is 2min.show at noon on monday,and is 4min.48 seconds fast at 2pm.on the follwing monday.when was it correct?
a)2 days 6hrs b)2 days 2 hrs c)3days 1hr d)3days 6hrs

The watch gains ( 2 min + 4 min 48 sec ) in 170 hours.( 7x24 + 2 =170 )
34/5 min is gained in 170 hours

2 min is gained in 50 hours.

So the watch will be correct at 2 days and 2 hours from noon on monday.
i.e. it will be correct on wednesday 2 pm.



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Old 20-05-06, 12:48 AM   #4 (permalink)
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q).in a garden there are 10 rows and 12 columns of mango trees. the distance btween each tree is 2 metres and a distance of one meter is left from all sides of the boundary of the garden. the length of the garden is

OPTIONS:_a)20 m b)22m c)24m d)26m

solution:



the length without considering the corners is 2(10)=20
with the consideration of boundary the length ll be 1+20+1=22

thus the length=22

breadth=26

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Old 20-05-06, 12:49 AM   #5 (permalink)
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cananyone explain 3rd problem....
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Old 20-05-06, 05:43 AM   #6 (permalink)
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dear u have said ki the length wud be 22
bt i m sorry its not like that , u r cosidering the breadth 10 rows means one below another and byconsidering them ull get the breadth
and second thingthe distance between10treesis 2*9 = 18

and if u include corners ull get18+1+1 =20


so if u want to find the lenght u have to consider the columns

and we get 2*11 = 22 +1+1=24

and if i m wronge please tell me

thanks
Edited by: iCanSolveIt
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