Does C have any Year 2000 problems

[ShivaniX]

Does C have any Year 2000 problems?

[retheeshsoman]

Dear Sivani,
No, The actual rules for the present Gregorian calendar are that leap years occur every four years, but not every 100 years, except that they do occur every 400 years, after all. In C, these rules can be expressed as:
year % 4 == 0 && (year % 100 != 0 || year % 400 == 0)
Actually, if the domain of interest is limited (perhaps by the range of a time_t) such that the only century year it encompasses is 2000, the expression
(year % 4 == 0) /* 1901-2099 only */
is accurate, if less than robust.
If you trust the implementor of the C library, you can use mktime to determine whether a given year is a leap year;
Note also that the transition from the Julian to the Gregorian calendar involved deleting several days to make up for accumulated errors. (The transition was first made in Catholic countries under Pope Gregory XIII in October, 1582, and involved deleting 10 days. In the British Empire, eleven days were deleted when the Gregorian calendar was adopted in September 1752. A few countries didn't switch until the 20th century.) Calendar code which has to work for historical dates must therefore be especially careful.

eg: Write a program to find whether an year is leap or not?
int leap(int year){
if(year % 4 == 0 && (year % 100 != 0 || year % 400 == 0))
return 1;
else
return 0;
}
int main(){
int year;
printf("Enter Year ?\n");
scanf("%d",&year);
if(leap(year))
printf("Leap Year \n");
else
printf("Non Leap \n");
}

output:
Enter Year ?
2000
Leap Year

Enter Year ?
2001
Non Leap