[WISDOM]

What's the output of the following program and why?

#include int main()
{
float a = 12.5;
printf("%d\n", a);
printf("%d\n", *(int *)&a);
return 0;
}

[poojareddy]

hey a is float value but ur giving %d
it will give error

[WISDOM]

plz note that though output may be wrong but this program will compile successfully. compiler won't give any error in this case. nothing much in this question.

[poojareddy]

hi
ok thank u for answering

[balanagireddy]

#include int main()
{
int a = 12;
printf("%d\n", a);
printf("%f\n", *(float *)&a);
return 0;
}

will this work?

[WISDOM]

float *p means pointer to a float. in this case 'a' happens to be an int, so this won't work. if u declare 'a' as float then this will be ok.
I think u can explain it better. so go ahead. thx for asking.