Plz help- C CODE needed

[VivekPandian]

1) Can anyone give me the C code for printing the nos 1..n , u must not use any recursion , loops, switch case or branching statements.

2) In 'C' , how to find the size of a structure without using the 'sizeof' operator. Also no instance of the strucure must be created?



Edited by: HELP

[sivakumar]

This code is for printing 1 to n.


voidprintUp(intstartNumber,intendNum ber)
{
start:

if(startNumber> endNumber)
{
gotoend;&amp ;nbs p;
}
else
{
printf("%d\n",&amp ;nbs p;startNumber++);
gotostart;&a mp;n bsp;
}

end:
return;
} Edited by: sivakumar

[VivekPandian]

I can't understand the code u gave. Can u explain it.
What does the & amp; &p; etc means????

Can U give me a solution that does not involve any if else statement (I mentioned it in the quesion??)

[sowmya571]

hello



In 'C' , how to find the size of a structure without using the 'sizeof' operator. Also no instance of the strucure must be created?



jus try this out



just declare a int variable after the structure..
and see the memory address.. remove 2 bytes from the address.. the
remaining is the size of the structure..



hope it shud work .This is what i have found .. i donno its
correct /not . jus check and post message 4 me if it works out



bye



sowmya

[aayushkaistha]

the method given by sowmya is not correct...


this is because if u declare an integer after the structure and display its address... its output would be something like 3150..


how can u guess the size of struct from that...


also if u declare an integer before and an integer after the structure.. even this wont work.. the difference between the address of the two integers will be 2 bytes...


this is because memory is not allocated to the structure but to its instances...


when we write the definition of a structure.. its only the definition and no memory is allocated. memory is allocated only when the instances of the structure are created...


i think we can only calculate teh size of the structure theoritically...


Eg: if we have a structure


struct a
{
int a;
float b;
char c[5];
};


a takes 2 bytes, b takes 4 bytes, c takes 5 bytes...


so the size of struct a is 11 bytes....


to calculate it through a program i think sizeof is necessary...

[sowmya571]

hello



its possible to find wait i will give the code!



bye



sowmya

[sowmya571]

hello



This is one way with instances



#include <stdio.h>

void main()

{

struct s{

int a;

float b;

char aa[10];

}s1,s2;



printf("size of s1 is : %d",sizeof(s1));

printf("%u \t %u",&s1,&s2);

printf("size of s2 is :%d",(char*)(void *)&s1-(char*)(void*)&s2);



}





This wd work .. But without creating intsances



I think its not possible with out creating any instance even by using
sizeof

In sizeof also we are using sizeof(sturct s // here indirectly we are
creating instance of structure) or sizeof(s1) ..

Where s1 is an instance of structure s ..

So we have to write a big program to take care of all the sizes and etc
etc to get this done ..

For more info just check the linux source code of sizeof .. That may
help you ..